(x+2)(x^2+8x-3)=0

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Solution for (x+2)(x^2+8x-3)=0 equation:


Simplifying
(x + 2)(x2 + 8x + -3) = 0

Reorder the terms:
(2 + x)(x2 + 8x + -3) = 0

Reorder the terms:
(2 + x)(-3 + 8x + x2) = 0

Multiply (2 + x) * (-3 + 8x + x2)
(2(-3 + 8x + x2) + x(-3 + 8x + x2)) = 0
((-3 * 2 + 8x * 2 + x2 * 2) + x(-3 + 8x + x2)) = 0
((-6 + 16x + 2x2) + x(-3 + 8x + x2)) = 0
(-6 + 16x + 2x2 + (-3 * x + 8x * x + x2 * x)) = 0
(-6 + 16x + 2x2 + (-3x + 8x2 + x3)) = 0

Reorder the terms:
(-6 + 16x + -3x + 2x2 + 8x2 + x3) = 0

Combine like terms: 16x + -3x = 13x
(-6 + 13x + 2x2 + 8x2 + x3) = 0

Combine like terms: 2x2 + 8x2 = 10x2
(-6 + 13x + 10x2 + x3) = 0

Solving
-6 + 13x + 10x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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